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use parents inFrustum status to optimize children

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This commit is contained in:
ZappoMan 2014-03-17 17:51:09 -07:00
parent 62dabd9c1c
commit c09974bcda
1 changed files with 10 additions and 2 deletions
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12
libraries/octree/src/Octree.cpp
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@ -892,6 +892,8 @@ int Octree::encodeTreeBitstreamRecursion(OctreeElement* node,
return bytesAtThisLevel;
}
}
ViewFrustum::location nodeLocationThisView = ViewFrustum::INSIDE; // assume we're inside
// caller can pass NULL as viewFrustum if they want everything
if (params.viewFrustum) {
@ -907,11 +909,13 @@ int Octree::encodeTreeBitstreamRecursion(OctreeElement* node,
params.stopReason = EncodeBitstreamParams::LOD_SKIP;
return bytesAtThisLevel;
}
nodeLocationThisView = node->inFrustum(*params.viewFrustum);
// If we're at a node that is out of view, then we can return, because no nodes below us will be in view!
// although technically, we really shouldn't ever be here, because our callers shouldn't be calling us if
// we're out of view
if (!node->isInView(*params.viewFrustum)) {
if (nodeLocationThisView == ViewFrustum::OUTSIDE) {
if (params.stats) {
params.stats->skippedOutOfView(node);
}
@ -1065,7 +1069,11 @@ int Octree::encodeTreeBitstreamRecursion(OctreeElement* node,
OctreeElement* childNode = sortedChildren[i];
int originalIndex = indexOfChildren[i];
bool childIsInView = (childNode && (!params.viewFrustum || childNode->isInView(*params.viewFrustum)));
bool childIsInView = (childNode &&
( !params.viewFrustum || // no view frustum was given, everything is assumed in view
(nodeLocationThisView == ViewFrustum::INSIDE) || // the parent was fully in view, we can assume ALL children are
(nodeLocationThisView == ViewFrustum::INTERSECT && childNode->isInView(*params.viewFrustum)) // the parent intersects and the child is in view
));
if (!childIsInView) {
// must check childNode here, because it could be we got here because there was no childNode